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Q3-5: Ethanoic acid reacts with ethanol in the presence of concentrated sulfuric acid.
4. The function of concentrated sulfuric acid is to ...
Q6: Methanoic acid and ethanol react to form an organic product.
6. The organic product formed is ...
7. The products of the reaction between ethanol and propanoic acid are ...
Q8+9 refer to the following structure:
Question 1:
The functional group of an ester is –COO- (specifically, R–COO–R', where R and R' are carbon-containing groups).
So the correct answer is:
B. –COO-
*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret. Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.
Question 2:
The correct answer is A. alcohol.
An ester is formed through a reaction called esterification, which occurs when a carboxylic acid reacts with an alcohol in the presence of an acid catalyst (usually concentrated sulfuric acid). This reaction produces an ester and water.
Question 3:
The correct answer is condensation (or esterification) reaction.
More specifically, it is a reversible esterification reaction, where ethanoic acid (acetic acid) and ethanol react in the presence of concentrated sulfuric acid (which acts as a catalyst and a dehydrating agent) to produce ethyl ethanoate (an ester) and water.
So the blank should be filled with: condensation.
Question 4:
The correct answer is D. act as a catalyst.
In the esterification reaction between ethanoic acid and ethanol, concentrated sulfuric acid serves two main purposes:
As a catalyst – it speeds up the reaction without being consumed.
As a dehydrating agent – it helps remove water, which pushes the equilibrium toward more ester formation.
However, since "act as a catalyst" is the only option that accurately describes its primary chemical function in this reaction (and it is not acting as an oxidizing or reducing agent), D is the correct choice.
Question 5:
The correct answer is B. ethyl ethanoate.
Here's why:
When ethanoic acid (CH₃COOH) reacts with ethanol (C₂H₅OH), the ester formed is ethyl ethanoate (CH₃COOC₂H₅).
The name of an ester is derived from:
The alkyl group from the alcohol (ethanol → ethyl)
The carboxylate part from the acid (ethanoic acid → ethanoate)
So together, they form ethyl ethanoate.
The other options are incorrect because:
A and C use "ethanoic" (which is the acid form, not the ester form).
D uses "ethanol" instead of "ethyl" (the alkyl group should be "ethyl", not "ethanol").
Question 6:
The organic product formed is A.
Reasoning:
The reaction between methanoic acid and ethanol is an esterification reaction.
In this process:
The -OH group from the methanoic acid and the -H from the alcohol's hydroxyl group combine to form water H2O.
The remaining fragments join to form an ester: ethyl methanoate.
Structural Breakdown:
Acid part: H-CO- (from methanoic acid)
Alcohol part: O-CH2-CH3 (from ethanol)
Resulting Ester: H-CO-O-CH2-CH3
Structure A correctly shows the carbonyl group C=O connected to an oxygen atom, which is then bonded to the ethyl group.
Question 7:
The correct answer is A. ethyl propanoate and water.
Here’s the reasoning:
You are reacting ethanol (an alcohol) with propanoic acid (a carboxylic acid).
In esterification, the alkyl group comes from the alcohol (ethanol → ethyl).
The carboxylate part comes from the acid (propanoic acid → propanoate).
Therefore, the ester formed is ethyl propanoate.
The other product is always water (H₂O) in this type of condensation reaction.
So the products are ethyl propanoate and water, which matches option A.
B and D suggest propyl (which would come from propanol, not ethanol).
C and D suggest hydrogen gas, which is not produced in esterification (water is produced instead).
Question 8:
Structure Analysis
The image shows an ester R-COO-R'.
Acyl part (left of the single-bonded O): Contains 2 carbons (ethan-).
Alkyl part (right of the single-bonded O): Contains 1 carbon (methyl-).
8. Reactants
This compound is formed by the reaction of an alcohol and a carboxylic acid.
Acid: Ethanoic acid (2 carbons)
Alcohol: Methanol (1 carbon)
Correct Answer: C. methanol and ethanoic acid
Question 9:
Esters are named as [alkyl] [alkanoate].
Alkyl group: Methyl
Alkanoate group: Ethanoate
Correct Answer: A. methyl ethanoate
Question 10:
The correct organic product is C.
Reasoning
The reaction between propanoic acid (\(\text{CH}_3\text{CH}_2\text{COOH}\)) and ethanol (\(\text{CH}_3\text{CH}_2\text{OH}\)) is an esterification reaction. This process removes a water molecule (\(\text{H}_2\text{O}\)), resulting in the formation of an ester:
\(\text{CH}_{3}\text{CH}_{2}\text{COOH}+\text{CH}_{3}\text{CH}_{2}\text{OH}\rightarrow \text{CH}_{3}\text{CH}_{2}\text{COOCH}_{2}\text{CH}_{3}+\text{H}_{2}\text{O}\)
Breakdown of Option C:
Acid part: The three-carbon chain on the left (\(CH_3-CH_2-C=O\)) comes from the propanoic acid.
Alcohol part: The two-carbon chain on the right (\(-O-CH_2-CH_3\)) comes from the ethanol.
Product Name: The resulting ester is ethyl propanoate.