Question 1:

The empirical formula gives the simplest whole number ratio of atoms in a compound.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 2:

The correct phrase is molecular formula.

The molecular formula shows the actual number of atoms of each element in a molecule of the compound.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 3:

To find the empirical formula, we need the simplest whole number ratio of moles of X to moles of Y.

Given:

• Moles of X = 0.2 mol

• Moles of Y = 0.4 mol

Step 1: Write the ratio

Step 2: Divide by the smallest number (0.2)

So the ratio is X₁Y₂.

Step 3: Empirical formula

Correct answer: B: XY₂

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 4:

To determine the simplest formula (empirical formula), follow these steps:

Step 1: Find moles of each element.

• Atomic mass of sulfur (S) ≈ 32 g/mol

• Atomic mass of oxygen (O) ≈ 16 g/mol

Moles of S=16 g, 32 g/mol=0.5 mol

Moles of O=24 g, 16 g/mol=1.5 mol

Step 2: Ratio of S : O

Step 3: Divide by smallest (0.5)

So the ratio is S₁O₃.

Step 4: Empirical formula

Correct answer: C: SO₃

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 5:

To find the molecular formula from the empirical formula and molar mass:

Step 1: Empirical formula mass of CH₂N₂

• C = 12, H = 1, N = 14

Step 2: Find the multiplier n

Step 3: Multiply empirical formula by n

Step 4: Match with options
C₃H₆N₆ corresponds to option C.

Correct answer: C: C₃H₆N₆

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 6:

Let’s find the empirical formula step by step.

Step 1: Assume 100 g of compound

• Mass of C = 85.7 g

• Mass of H = 14.3 g

Step 2: Convert to moles

• Moles of C = 85.7/12≈7.14 mol

• Moles of H = 14.3/1=14.3 mol

Step 3: Divide by smallest (7.14)

So the ratio is C : H = 1 : 2.

Step 4: Empirical formula

Correct answer: B: CH₂

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 7:

Let’s determine the molecular formula from the empirical formula and the molar mass.

Step 1: Empirical formula already found
From the previous question: empirical formula = CH₂
Empirical formula mass = 12 + (2 × 1) = 14 g/mol

Step 2: Use given molecular mass
Relative molecular mass = 42 g/mol

Step 3: Multiply empirical formula by n

Step 4: Match with options
C₃H₆ is option D.

Correct answer: D: C₃H₆

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 8:

Step 1: Find moles of magnesium atoms used

Mass of Mg = 0.12 g
Atomic mass of Mg ≈ 24 g/mol

Step 2: Find moles of oxygen atoms in the magnesium oxide

Mass of MgO formed = 0.20 g
Mass of oxygen in MgO = Mass of MgO − Mass of Mg = 0.20−0.12=0.08 g

Atomic mass of O = 16 g/mol

Step 3: Compare with the options

Moles of Mg = 0.005, Moles of O = 0.005 ⇒ matches option A.

Final answer: A (0.005, 0.005)

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 9:

Step 1: Find mass of oxide of copper before heating
Mass of boat + oxide before heating = 24.0 g
Mass of boat = 20.0 g

Mass of oxide = 24.0−20.0=4.0 g

Step 2: Find mass of copper after heating
Mass of boat + copper after heating = 23.2 g

Mass of copper = 23.2−20.0=3.2 g

Step 3: Find mass of oxygen in original oxide
Mass of oxygen = Mass of oxide − Mass of copper
4.0−3.2=0.8 g

Step 4: Match with options
Copper = 3.2 g, Oxygen = 0.8 g → Option D

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 10:

Let’s determine the formula from the masses found in the previous question.

Step 1: Masses from Question 9
Mass of copper = 3.2 g
Mass of oxygen = 0.8 g

Step 2: Convert to moles
Atomic mass Cu = 64 g/mol, O = 16 g/mol

Moles of Cu = 3.2/64=0.05 mol
Moles of O = 0.8/16=0.05 mol

Step 3: Ratio of Cu : O

Step 4: Empirical formula
CuO

Final answer: A: CuO

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.