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Q 1-3:

Here are 4 distance-time graphs showing the movement of some athletes:

s-t graphs x4

Which of these shows...

 

1. an athlete moving away at constant speed?

2. a stationary athlete?

3. an athlete slowing down and stopping?

4. The speed or velocity of any object can be measured in ...

  • A. m/s2
  • B. N
  • C. m/s
  • D. m

Q5-7:

Here are some more graphs, showing velocity-time.

v-t graphs x 4

Which of these shows ...

 

5. a constant velocity?

6. a uniform deceleration?

7. a falling tennis ball reaching terminal velocity?

 

8. Velocity-time graphs can be used to calculate the acceleration and the distance travelled. Which row in the table below shows how is this done?

To Find The Distance: To Find The Acceleration:
A
Area under the line Length of line
B
Length of line Gradient of line
C
Gradient of line Length of line
D
Area under the line Gradient of line

This graph shows a cyclist's velocity during the first 20 seconds of a bike race:

v-t graph for a bike

cyclists

9. What was the acceleration of the cyclist?

  • A. 0.6 m/s2
  • B. 1.6 m/s2
  • C. 120 m/s2
  • D. 240 m/s2

10. How far did the cyclist travel in the first 20s?

  • A. 0.6 m
  • B. 1.6 m
  • C. 120 m
  • D. 240 m
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Question 1:

On a distance–time graph (distance on the vertical axis, time on the horizontal axis):

  1. An athlete moving away at constant speed:
    → A straight line sloping upwards (positive slope).

    The slope of the line equals the constant speed.

    The greater the speed, the steeper the line.

    This matches option B.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
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Question 2

A stationary athlete → A horizontal line (zero slope).

Distance does not change as time increases.

The line is flat at the distance value where the athlete is stationary.

This matches option A.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
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Question 3:

An athlete slowing down and stopping
→ A curve that starts steep (moving faster), then gets less steep (slowing down), and finally becomes horizontal (stopped).

This matches option D.

Note: The line does not move down towards the time axis, because the distance is always increasing. (Distance is a scalar quantity).


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
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Question 4:

The correct answer is:

C. m/s (metres per second)


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
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Question 5:

A constant velocity
→ A horizontal straight line (zero slope).

This matches option A.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
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Question 6:

A uniform deceleration
→ A straight line sloping downwards (constant negative slope).


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
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Question 7:

A falling tennis ball reaching terminal velocity (downwards positive)
→ A curve that starts steep (large positive slope → large acceleration due to gravity), then the slope gradually decreases (air resistance increases), finally becoming horizontal.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
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Question 8:

The correct answer is:

D


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 9:

Use the acceleration formula:

a=Δv/Δt=12/20 =0.6 m/s2

Note: this is the same as the gradient, (change in y)/(change in x).

✅ A. 0.6 m/s²


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 10:

For constant acceleration from rest:

distance=average velocity×time

vavg=(0+12)/2=6 m/s

distance=6×20=120 m

Or, area under velocity–time graph (triangle):

Area=½×base×height=½×20×12=120 m

✅ C. 120 m


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.