Target: 10 Questions in 10 minutes

An IB Physics data booklet is helpful

 

Q1-5: A tennis ball - initially at rest - is dropped from a height of 5 m.

Air resistance is negligible as it falls.

 

tennis ball

 1. Which of these answers correctly labels the letters 's', 'v' and 'u' in the 'suvats' equations?

  • A. s= speed, v = initial velocity, u = final velocity
  • B. s= speed, v = final velocity, u = initial velocity
  • C. s= displacement, v = initial velocity, u = final velocity
  • D. s= displacement, v = final velocity, u = initial velocity

2. Which of these answers correctly gives the approximate values for 's', and 'u' and 'a' in the 'suvats' equations? (No units are given).

  • A. s= 0, a= 0, u = 0
  • B. s= 0, a = 10, u = 0
  • C. s= 5, a = 10, u = 0
  • D. s= 5, a = 10, u = 10

3. Which of these equations can be used without further calculation to find the impact velocity?

  • A. v = u + at
  • B. s= ut + ½ at2
  • C. v2 = u2 + 2as
  • D. s = ½ (u+v).t

4. What is the impact velocity of the ball?

  • A. 5 ms-1
  • B. 10 ms-1
  • C. √50 ms-1
  • D. 100 ms-1

5. How long did it take for the ball to fall to the ground?

  • A. 2 s
  • B. 0.5 s
  • C. 1 s
  • D. 10 s


6&7. A ball is rolled down a steep slope. The initial velocity is 2 ms-1 and it accelerates at a rate of 4 ms-2 for 5 seconds.

 

6. What is the final velocity of the ball?

  • A. 20 ms-1
  • B. 22 ms-1
  • C. 24 ms-1
  • D. 10 ms-1

7. How far does the ball roll in this time?

  • A. 8 m
  • B. 28 m
  • C. 50 m
  • D. 60 m

 

8-10. A stone is thrown horizontally at 10 ms-1 from a cliff of height 5 m.

Air resistance can be ignored.

 

projectile thrown from cliff

8. Which of these correctly describes the changes in the horizontal and vertical components of velocity of the stone?

Horizontal velocity Vertical velocity
A
constant increasing
B
increasing constant
C
constant constant
D
decreasing increasing

9. What is the vertical velocity of the stone on impact?

  • A. 5 ms-1
  • B. 10 ms-1
  • C. √50 ms-1
  • D. 100 ms-1

10. The stone takes 1 second to reach the ground. How far from the cliff edge does the stone land?

  • A. 10 m
  • B. 20 m
  • C. 30 m
  • D. 40 m
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Question 1:

The letters in the suvat equations (which are used to solve problems involving motion with constant acceleration) represent:

s = displacement

u = initial velocity

v = final velocity

a = constant acceleration

t = time

The correct answer is D.


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Question 2:

Explanation of SUVAT values for a dropped object
Defining the variables
s is the displacement, which is the change in position.

u is the initial velocity.

v is the final velocity.

a is the acceleration.

t is the time.

Analysis of the problem
s: The ball is dropped from a height of 5 m, so the displacement s is 5 m.

u: The ball is initially at rest, meaning its initial velocity u is 0.

a: The ball is under the influence of gravity. The acceleration due to gravity, a, is approximately 10 m/s2. The problem states that air resistance is negligible, so the only force acting on the ball is gravity.

The correct answer is C. The values for s, a, and u are 5, 10, and 0 respectively.


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Question 3:

Explanation of SUVAT equations

To find the final velocity without any further calculations, you need an equation that relates the known values to the unknown value you are trying to find.

Therefore, the only equation that can be used to find the impact velocity directly,
without needing to calculate time first, is .

The correct equation is C. .



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Question 4:

Calculation

Using the kinematic equation , where:

We can substitute these values into the equation:

To find the final velocity, take the square root of both sides:

The calculated impact velocity is , which matches option B.


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Question 5:

Calculation
To find the time it took for the ball to fall, we can use the kinematic equation s=ut+½at 2 .

s is the displacement, which is 5 m.

u is the initial velocity, which is 0 m/s because the ball was at rest.

a is the acceleration due to gravity, approximately 10 m/s2 .

t is the time we want to find.

Substitute the known values into the equation:

5=(0)t+ ½(10)t2

5=5t2

Now, solve for t:

t2=1
so t=1s

The calculated time is 1s, which corresponds to option C.


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Question 6:

Calculation
To find the final velocity of the ball, we can use the kinematic equation v=u+at.

v is the final velocity (what we need to find).

u is the initial velocity, which is 2 m/s.

a is the acceleration, which is 4 m/s2 .

t is the time, which is 5 s.

Substitute the known values into the equation:
v=2+(4)(5)
v=2+20
v=22 m/s

The calculated final velocity is 22 m/s, which matches option B.


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Question 7:

Calculation

To find how far the ball rolls, we can use the kinematic equations s = ut + ½at2.

Substitute the known values into the equation:

The calculated displacement is , which matches option D.


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Question 8:

Explanation of Projectile Motion

In projectile motion, such as a stone thrown horizontally from a cliff, the horizontal and vertical motions are independent of each other.


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Question 9:

Calculation
To find the vertical velocity of the stone on impact, we need to consider only the vertical component of the motion. We can use the kinematic equation v2 = u2 + 2as for the vertical direction.

v is the final vertical velocity (what we need to find).

u is the initial vertical velocity, which is 0 m/s because the stone is thrown horizontally.

a is the acceleration due to gravity, approximately 10 m/s2.

s is the vertical displacement, which is 5 m.

Substitute the values into the equation:
v2 =(0)2+2x10x5
v2=0+100
v2 =100

To find the final vertical velocity, take the square root of both sides:
v= sqrt100
v=10 m/s

The calculated final vertical velocity is 10 m/s, which matches option B.


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Question 10:

Calculation
To find the horizontal distance the stone travels, we only need to consider the horizontal motion. Since air resistance is ignored, the horizontal velocity remains constant. The formula for distance is:
distance=velocity x time

Horizontal velocity is 10 m/s.

Time is 1 s.

Distance =10 m/s x 1 s
Distance =10 m

The stone lands 10 m from the edge of the cliff.

The correct answer is A, 10 m.


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